Four cells, each of e.m.f. 1.5 V and internal resistance 2.0 ohms are connected in … The drop in potential across-the terminals of…
Answers:
E.m.f. of cell (each) = 1.5 V. and also e.m.f. of all four cells = 1.5V, internal resistance of each cell = 2.0 ohm.
Total internal resistance of all four cells
1/r1 = 4/r = 4/2.0 = 2.0 ohm
∴ r1 = ½ = 0.5 ohm
(i) ∴ Total resistance of circuit = R + r
= 2.5 + 0.5 = 3.0 ohm
(ii) Current flowing in the external circuit
I = E/r = 1.5/2.5 = 0.6 Amp.
(iii) The drop in potentials across the terminals of the cells.
= I x r/4 = 0.6 x 2/4 = 0.6 x 0.5 = 0.30 Volt .