Force between two identical bar magnets whose centres are r meter apart is 4.8 N, when their axes are in the same line. … 2 N (c)…
Answers:
The correct option (d) 0.3 N
Explanation:
Force between two magnetic dipole ∝ (1/r4)
∴ (F2/F1) = (r1/r2)4
Given r1 = r
r2 = 2r
F1 = 4.8N
∴ F2 = 4.8 × (r/2r)4 = 4.8 × (1/16)
F2 = 0.3 N