Ax2 4a2 3b X 12ab 0

ax2 + (4a2 – 3b)x – 12ab = 0

Answers:

Here  ax² + (4a² – 3b)x – 12ab = 0

⇒ ax² +  4a²x  – 3bx – 12ab = 0

⇒ ax ( x + 4a) – 3b(x + 4a) = 0

⇒ (ax – 3b)(x + 4a)= 0

⇒ x = 3b/a   or – 4a are two roots of equation.