Average Kinetic Energy Of Gas Molecule At 27в°C Is 6 21 10 21 J

The average kinetic energy of a gas molecule at 27°C is 6.21 10-21 J. Its average kinetic energy at 227°C will … 2 10-21J …

Answers:

The correct option (D) 12.42 × 10^–21J

Explanation:

 Average kinetic energy ∝ Temperature

E ∝ T

 (E₂/E₁) =(T₂/T₁)

as  T₂ = 327 + 273 = 600K

T₁ = 27 + 273 = 300K

 ∴ (E₂/E₁) = (600/300)

 ∴ E₂ = 1 × 6.21 × 10^–21 × 2

 E₂ = 12.42 × 10^–21J