Attempt this question on graph paper. Marks obtained by 200 students in examination are given below: … , find the minimum marks…
Answers:
(i) Let A be the point on y – axis representing frequency
Here, n (no. of students) = 200 (even)
Median = (n/2)th term
= (200/2)th term
= 100th term
From the graph 100th term = 57.5
(ii) Upper quartile = 3n/4
= (3 × 200th)/4 term
= 600/4 = 150th term
From graph 150th term = 72
The upper quartile = 72
(iii) No. of students scoring above 65 marks
⇒ Total No. of students – No. of students scoring ≤ 65 marks
⇒ 200-126
⇒ 74 (approx.)
(iv) From the above diagram, we observe the students from 191 to 200 qualify for merit scholarship.
∴ The students who qualifies for merit scholarship scores more than 91 marks.
∴ The minimum marks required to qualify for merit scholarship
= 92 (approx.)