At what temperature volume of an ideal gas becomes triple (A) 819°C (B) 182°C (C) 646°C (D) 546°C
Answers:
The correct option (D) 546°C
Explanation:
At constant press use
V ∝ T
(V2/V1) = (T2/T1)
given: V2 = 3V1
∴ 3 = (T2/T1)
∴ T2 = 3 T1
= 3 × 273 K
T2 = 819 K
i.e. T2 = (819 – 273)°C
i.e. T2 = 546°C