At what distance from a concave mirror of focal length 10 cm should an object be placed so that: … virtual image is formed 20 cm…
Answers:
(a) f = -10 cm
v = – 20 cm (real image)
1/v + 1/u = 1/f
1/-20 + 1/u = 1/-10
1/u = -1/10 + 1/20 = -1/20
u = -20 cm
(b) f = -10 cm
V = 20 cm (virtual image)
1/v + 1/u = 1/f
1/20 + 1/u = 1/-10
1/u = -1/10 + -1/20 = -3/20
u = -(20/3) cm