An arrow 2.5 cm high is placed at a distance of 25 cm from a diverging mirror of focal length … the nature, position and size of the…
Answers:
h1= 2.5cm, u = -25cm, f = 20cm
We know that
1/v + 1/u = 1/f
⇒ 1/v + 1/-25 = 1/20
⇒ 1/v = 1/25 + 1/20 = (4 + 5)/100 = 9/100
∴ v = (100/9) cm = 11.1 cm
The image is formed 11.1 cm behind the convex mirror.
Now,
m = – (v/u) = h2/h1
⇒ – (11.1/-25) = h2/2.5
⇒ h2 = (11.1 × 2.5)/25 = 1.11 cm
The image is virtual, erect and 1.11 cm tall.