The area of the region bounded by parabola y2 = x and the straight line 2y = x is (a) 4/3 sq. units (b) … (c) 2/3 sq. units (d) 1/3…
(a) We have y2 = x and 2y = x
Solving, we get y2 = 2y
⇒ y = 0,2
When y = 0, x=0 and when y = 2, x = 4
So, points of intersection are (0,0) and (4,2)
Graphs of parabola y2 = x and 2y = x are as shown in the following figure.