Are the points (-2, 2), (8, -2) and (-4, 3) are the vertices of a right angled triangle.
Answers:
Let the points A(-2,2), B(8,-2)and C(-4,3) be the vertices of a triangle ABC.
AB2 = (8+2)2 + (-2-2)2 = 102 + 42 = 100 + 16 = 116
BC2 = (-4-8)2 + (3+2)2 = (-12)2 + 52 = 144 + 25 = 169
AC2 = (-4+2)2 + (3-2)2 = (-2)2 + 1 = 4 + 1 = 5
AB2 + AC2 ≠ BC2
The above vertices are not points of a right angled triangle.