**Are the points (-2, 2), (8, -2) and (-4, 3) are the vertices of a right angled triangle.**

###### Answers:

Let the points A(-2,2), B(8,-2)and C(-4,3) be the vertices of a triangle ABC.

AB^{2} = (8+2)^{2} + (-2-2)^{2} = 10^{2 }+ 4^{2} = 100 + 16 = 116

BC^{2} = (-4-8)^{2} + (3+2)^{2} = (-12)^{2} + 5^{2} = 144 + 25 = 169

AC^{2 }= (-4+2)^{2} + (3-2)^{2} = (-2)^{2} + 1 = 4 + 1 = 5

AB^{2} + AC^{2} ≠ BC^{2}

The above vertices are not points of a right angled triangle.