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Angular Velocity Particle Given 3t2 Time When Angular Acceleration Ceases Zero Will Sec

The angular velocity of a particle is given by ω = 1.5 t -3t2 + 2 the time when its angular acceleration ceases … . 25 sec (c) 12…

Answers:

Correct Option  (b) 0. 25 sec

 Explanation:

ω = 1.5t – 3t2 + 2 and α = d ω/dt

= 1.5 t – 6t ⇒ 0 = 1.5 – 6t

∴ t = 1.5/6 = 0.25 sec


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