**The angle of elevation of the top Q of a vertical tower PQ from point X on the ground is 60 … elevation is 45 degree .Find the height…**

###### Answers:

In YRQ, we have

⇒ YR = *x*

or XP = *x* [ As YR = XP ] …… (1)

Now, In ∆ XPQ, we have

On rationalising the denominator, we get

So, height of the tower, PQ = *x* + 40 = 54.64 + 40 = 94.64 metres

Now in ∆ XPQ, we have