ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Then prove that area (△BDE) = 1/4 area (△ABC)
Answers:
Solution :-√
Let the side of triangle, BC = a ⇒ BD = a/2
area(△BDE) = √3/4 (a/2)2
= √3/4.a2/4 = 1/4 (√3/4.a2)
area(△BDE ) = 1/4 area (△ABC)