X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a … figure). Prove that : ar(△LZY) =…
Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM).
∴ ar(△XZL) = ar(△XZM)
Adding ar(△XZY) on both sides , we have
ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY)
⇒ ar(△LZY) = ar(quad.MZYX)