Amplitude Of Magnetic Field Part Of Electromagnetic Wave In Vacuum Is Bm 510 Nt

The amplitude of the magnetic field part of an electromagnetic wave in vacuum is Bm = 510 nT. Then the amplitude of … 102 V/m (D)…

Answers:

The correct option is (C) 1.53 × 102 V/m

Explanation:

 Bm = 510 nT = 510 × 10–9T

 Amplitude of electric part is Em 

 & (Em / Bm) = C 

 Hence Em = C × Bm 

= 3 × 108 × 510 × 10–9 

= 153 V/m

  = 1.53 × 102 V/m