The amplitude of the electric field in a parallel beam of light of intensity 2.0 Wm-2 is ________ (A) 38.8 … 1 (C) 9.7 NC-1 (D)…
Answers:
The correct option is (A) 38.8NC–1.
Explanation:
Eo = √(2I / EoC)
As I = intensity = 2 W/m2
Eo = 8.85 × 10–12
C = 3 × 108 m/s
Eo = √[(2 × 2) / (8.85 × 10–12 × 3 × 108)]
= √(1506.59)
= 38.81 N/C