An alternating voltage E = 200√2 sin (100t) is connected to 1 microfarad capacitor through an ac ammeter. The reading … 20 mA (c)…
Answers:
The correct option (b) 20 mA
Explanation:
E = 200√2 sin 100t
Hence
ω = 100 rad/sec
and
Erms = [{200√2}/{√2}]
C = 1 × 10–6 F
XC = (1/ωC) = [1/{100 × 1 × 10–6}] = 104 Ω
I = (Erms/Z)
= [{(200√2)/√2}/{104}]
= [{200}/{104}]
= 2 × 10–2 A
∴ I = 20 mA.