**Air is filled at 60°C in a vessel of open mouth. The vessel is heated to a temperature T so that (1/4)th … A) 333°C (B) 171°C …**

###### Answers:

The correct option (B) 171°C

Explanation:

For open mouth Vessel, pressure is constant. Volume is also given to be constant PV = nRT

∴ PV = {MRT/M_{o}}

∴ MT = constant

∴ (T_{1}/T_{2}) = (M_{2}/M_{1}) (1)

As (1/4) th part escapes, mass remained is (3/4) m_{1} i.e. M_{2} = (3/4) m_{1}

∴ (T_{1}/T_{2}) = [{(3/4) M_{1}} / M_{1}] = (3 / 4)

also T_{1} = 60°C = 273 + 60 = 333 K

∴ T_{2} = (4/3) T_{1}

= (4/3) × 33 = 444 K

∴ T_{2 }= 171°C