ABCD is a trapezium with parallel sides AB = a cm and DC = b cm . E and F are the mid – points of … . Find the ratio of ar(ABFE) and…
Answers:
Clearly, EF = AB + DC / 2 = a + b / 2
Let h be the height , then
ar(Trap. ABFE) : ar(Trap. EFCD)
⇒ 1/2 [a + (a+b / 2)] × h : 1/2 [b + (a+b / 2)] × h
⇒ 2a + a + b / 2 : 2b + a + b / 2
⇒ 3a + b : 3b + a