**closed**

###### Answers:

Given,

AC is the common hypotenuse. ∠B = ∠D = 90°.

To prove,

∠CAD = ∠CBD

Proof:

Since, ∠ABC and ∠ADC are 90°. These angles are in the semi circle. Thus, both the triangles are lying in the semi circle and AC is the diameter of the circle.

⇒ Points A, B, C and D are concyclic.

Thus, CD is the chord.

⇒ ∠CAD = ∠CBD (Angles in the same segment of the circle)

Given,

AC is the common hypotenuse. ∠B = ∠D = 90°.

To prove,

∠CAD = ∠CBD

Proof:

Thus, CD is the chord.

⇒ ∠CAD = ∠CBD (Angles in the same segment of the circle)