50 Of Metal Piece At 27в°C Requires 2400 J Of Heat Energy So As To Attain Temperature Of 327в°C

50 g of metal piece at 27°C requires 2400 J of heat energy so as to attain a temperature of 327°C. Calculate the specific heat…

Answers:

m = 50 g or 50/1000 kg

H = 2400 J

Q1 = 270C

Q2 = 3270 C

H = mcθ

c = H/mθ = 2400/50/1000 x (327 – 27)

= 2400/5/100 x 300    

= 2400/15 = 160 J/Kg – K