50 G Of Ice At 0в°C Is Added To 300 G Of Liquid At 30в°C

50 g of ice at 0°C is added to 300 g of a liquid at 30°C. What will be the final temperature of … Specific latent heat of fusion of…

Answers:

m₁ = 50g, t₁ = 0⁰C, m₂ = 300g , t₂ = 30⁰C

Heat energy taken by ice to melt = 50 x 336 J = 16800 J

By law of conservation of energy.

Heat energy given by liquid = Heat taken by water

300 x 2.65 x (30 – t) = 16800 + 50 x t x 4.2

⇒ 23850 – 795t = 16800 + 210 t

⇒  – 795 t – 210 t = 16800 – 23850

⇒ – 1005 t = – 7050

⇒  t = 7050/1005 = 7.014⁰C