50 g of ice at 0°C is added to 300 g of a liquid at 30°C. What will be the final temperature of … Specific latent heat of fusion of…
Answers:
m1 = 50g, t1 = 00C, m2 = 300g , t2 = 300C
Heat energy taken by ice to melt = 50 x 336 J = 16800 J
By law of conservation of energy.
Heat energy given by liquid = Heat taken by water
300 x 2.65 x (30 – t) = 16800 + 50 x t x 4.2
⇒ 23850 – 795t = 16800 + 210 t
⇒ – 795 t – 210 t = 16800 – 23850
⇒ – 1005 t = – 7050
⇒ t = 7050/1005 = 7.0140C