4th Term From End Of Ap 11 8 5 49 Is

The 4th term from the end of an AP – 11, -8,-5,…, 49 is (a) 37 (b) 40 (c) 43 …

Answers:

(b) We know that, the n th term of an AP from the end is
an = l – (n-1)d
Here, l = Last term and l = 49
Common difference, d = -8-(-11)
= -8 + 11 = 3
From Eq. (i), a₄ = 49 – (4-1)3 = 49 – 9 = 40