40g of ice at 0°C is used to bring down the temperature of a certain mass of water at 60°C to 10°C. Find … of fusion of ice = 336…
Answers:
Let mass of water used = m gm.
By principle of calorimetry,
Heat given = Heat taken
m1c1ΔQ1 = mL + m2c2ΔQ2
m x 4.2 x (60 – 10) = 40 x 336 + 40 x 4.2 x (10 – 0)
m x 4.2 x 50 = 40 x 336 + 1680
m = 72 gm