250 g of water at 30 °C is present in a copper vessel of mass 50 g. Calculate the mass of ice required … heat capacity of water =…
Answers:
Given, water = 250 gm
= 300 C
mass of vessel = 50 gm.
Final temperature = 50C
By the principle of calorimetry .
Heat given = Heat taken,
Let mass of ice = m gm
250 x 4.2 x (30 – 5) + 50 x 0.4 x 25 = m x 336 + m x 4.2 x 5
26250 + 500 = 336m + 21m
26750 = 357m.
m = 74.9 gm