200 G Of Hot Water At 80в°C Is Added To 300 G Of Cold Water At 10 В°C

200 g of hot water at 80°C is added to 300 g of cold water at 10 °C. Calculate the final temperature … heat capacity of water is…

Answers:

Given Hot water m = 200 g, temperature = 80⁰C

Cold water m = 300g, temperature = 10⁰C

Let final temperature of mixture = θ.

By the principle of calorimetry

Heat given = Heat taken

200 x c x (80 – θ) = 300 x c x (θ – 10)

200 x 80 – 200θ = 300θ – 300 x 10

16000 – 200θ = 300θ – 3000

19000 = 500θ

θ = 38⁰C