**20 g of ice at 0°C is added to 200g of water at 20°C. Calculate the drop in temperature ignoring the … . (Specific latent heat of…**

###### Answers:

Let x be the drop in temperature of water

Heat lost by water = 200 × x

Heat gained by ice in melting = 20 x 80 = 1600 calories

Heat gained by water from ice in rising from 0^{0}C to (20 – x)^{0}C = 20 x 1 x (20 – x)

∵ Heat gained = Heat lost

∴ 200 × x = 20 x 80 + 20(20 – x)

Or 200x + 20x = 400 + 1600

x = 2000/220 = 9.1^{0}C