20 G Of Ice At 0в°C Is Added To 200g Of Water At 20в°C

20 g of ice at 0°C is added to 200g of water at 20°C. Calculate the drop in temperature ignoring the … . (Specific latent heat of…

Answers:

Let x be the drop  in temperature of water

Heat lost by water  = 200 × x

Heat  gained by ice in melting  = 20  x  80 = 1600 calories

Heat gained by water from ice in rising from 0⁰C to (20 – x)⁰C = 20  x 1 x (20 – x)

∵ Heat gained = Heat lost

∴  200 × x = 20 x 80 + 20(20 – x)

Or 200x + 20x = 400 + 1600

x = 2000/220 = 9.1⁰C