A 2.0 cm tall object is placed 40 cm from a diverging lens of focal length 15 cm. find the position and size of the image.
Answers:
h1 = 2 cm
u = -40 cm
f = -15 cm
1/v – 1/u = 1/f
1/v – 1/-40 = 1/-15
1/v = – (1/15) – 1/40
1/v = -11/120
V = -10.90 cm
m = v/u = h2/h1
-10.90/-40 = h2/2
h2 = 0.54 cm