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150 G Of Ice Is Mixed With 100 G Of Water At Temperature 80вє C

150 g of ice is mixed with 100 g of water at temperature 80º C. The latent heat of ice is 80 cal/g and the specific … (B) 0 g (C)…

Answers:

Correct option (D) 50 g

Explanation:

 Heat loss by water = heat gain by ice. 

 100 × 1 × 80 = m × 80 

 m = 100 gm ice melt 

 ∴ Remaining ice = 50 g 


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