11th Term Of Ap 5 5 2 0 5 2

The 11th term of an AP – 5,-5/2,0,5/2… (a)-20 (b) 20 (c)-30 …

Answers:

Given AP,-5,-5/2,0,5/2
Here, a = -5, d = -5/2 + 5 = 5/2
a₁₁ = a + (11-1)d  [∵a_n = a + (n-1)d]
= -5 + (10) × 5/2
= -5 + 25 = 20.