1000 tickets of a lottery were sold and there are 5 prizes on these tickets. If Namita has … ticket, what is the probability of…
Answers:
n(S) = 1000
n(E) = 5
P(E) = ?
∴ P(E) = n(E)/n(S)
= 5/1000 = 0.005
1000 tickets of a lottery were sold and there are 5 prizes on these tickets. If Namita has … ticket, what is the probability of…
n(S) = 1000
n(E) = 5
P(E) = ?
∴ P(E) = n(E)/n(S)
= 5/1000 = 0.005